(2x^4+4x^3-8)-(6x^2-3x+8)=

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Solution for (2x^4+4x^3-8)-(6x^2-3x+8)= equation: 


Simplifying
(2x4 + 4x3 + -8) + -1(6x2 + -3x + 8) = 0

Reorder the terms:
(-8 + 4x3 + 2x4) + -1(6x2 + -3x + 8) = 0

Remove parenthesis around (-8 + 4x3 + 2x4)
-8 + 4x3 + 2x4 + -1(6x2 + -3x + 8) = 0

Reorder the terms:
-8 + 4x3 + 2x4 + -1(8 + -3x + 6x2) = 0
-8 + 4x3 + 2x4 + (8 * -1 + -3x * -1 + 6x2 * -1) = 0
-8 + 4x3 + 2x4 + (-8 + 3x + -6x2) = 0

Reorder the terms:
-8 + -8 + 3x + -6x2 + 4x3 + 2x4 = 0

Combine like terms: -8 + -8 = -16
-16 + 3x + -6x2 + 4x3 + 2x4 = 0

Solving
-16 + 3x + -6x2 + 4x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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